SOLVED: import java.util.Scanner; public class Hw1pr4 public static void main(String[] args) Scanner in = new Scanner(System.in); System.out.print("Please enter your name:"); String str = in.nextLine(); int position; int length; if (str.length() % 2 ==
Java Scanner findInLine(String pattern) method example
SOLVED: “`java import java.util.Scanner; public class LastVowel public static void main(String[] args) Scanner in = new Scanner(System.in); String word = in.next(); int position = ...; while (...) if (ch == 'a'
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